In your original post, answer the following:
Electronic Devices
10th ed.
Chapter 7
BJT Power Amplifiers
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Copyright © 2018 Pearson Education, Inc. All Rights Reserved
Electronic Devices
10th ed.
◆ Explain and analyze the operation of class A amplifiers
◆ Explain and analyze the operation of class B and class AB
amplifiers
◆ Explain and analyze the operation of class C amplifiers
◆ Troubleshoot power amplifiers
Objectives:
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Copyright © 2018 Pearson Education, Inc. All Rights Reserved
Electronic Devices
Power Amplifiers
A power amplifier is a large signal amplifier that produces a replica of the input signal on its output. In the case shown here, the output is an inverted replica of the input.
Generally power amplifiers are defined as those in which it is necessary to consider the problem of heat dissipation (about 1 W or more).
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Electronic Devices
Class-A Power Amplifiers
A class A power amplifier is a large signal amplifier that operates in the linear region. Ideally, a class A amplifier is
designed to operate in the center of the ac load line.
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Electronic Devices
Class-A Power Amplifiers
A class A power amplifier is a large signal amplifier that operates in the linear region. Ideally, a class A amplifier is
designed to operate in the center of the ac load line.
Notice that a class A amplifier dissipates dc power even with no signal. The dc power dissipated is the product of ICQ and VCEQ.
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Electronic Devices
Class-A Power Amplifier Efficiency
Power gain is the ratio of the power delivered to the load to the input power. The maximum signal power delivered to a load cannot be greater than 0.5 ICQVCEQ.
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Electronic Devices
Class-A Power Amplifier Efficiency
Power gain is the ratio of the power delivered to the load to the input power. The maximum signal power delivered to a load cannot be greater than 0.5 ICQVCEQ.
Class A power amplifiers are not particularly efficient, so they are restricted to low power applications. The maximum theoretical efficiency for a class A amplifier is 0.25 (or 25%) and usually they are considerably less.
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Electronic Devices
Class-A Power Amplifier Efficiency
Power gain is the ratio of the power delivered to the load to the input power. The maximum signal power delivered to a load cannot be greater than 0.5 ICQVCEQ.
Class A power amplifiers are not particularly efficient, so they are restricted to low power applications. The maximum theoretical efficiency for a class A amplifier is 0.25 (or 25%) and usually they are considerably less.
Question:
What is the efficiency of an amplifier that delivers 200 mW to a load if the power supply is 12 V at 400 mA?
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Electronic Devices
Class-A Power Amplifier Efficiency
Power gain is the ratio of the power delivered to the load to the input power. The maximum signal power delivered to a load cannot be greater than 0.5 ICQVCEQ.
Class A power amplifiers are not particularly efficient, so they are restricted to low power applications. The maximum theoretical efficiency for a class A amplifier is 0.25 (or 25%) and usually they are considerably less.
Question:
What is the efficiency of an amplifier that delivers 200 mW to a load if the power supply is 12 V at 400 mA?
6.7%
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Electronic Devices
Class-A Power Amplifier – Example
(a) If a 3 Vpp signal is applied to the input, what voltage do you expect to see at the speaker? (b) What power is delivered?
Example:
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Electronic Devices
Class-A Power Amplifier – Example
(a) If a 3 Vpp signal is applied to the input, what voltage do you expect to see at the speaker? (b) What power is delivered?
Solution:
Example:
(a) The CC amplifier has a gain of nearly 1. The output voltage is nearly equal to the input = 3 Vpp.
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Electronic Devices
Class-A Power Amplifier – Example
(a) If a 3 Vpp signal is applied to the input, what voltage do you expect to see at the speaker? (b) What power is delivered?
Solution:
Example:
(a) The CC amplifier has a gain of nearly 1. The output voltage is nearly equal to the input = 3 Vpp.
(b) The power delivered to the speaker is:
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Electronic Devices
Class-A Power Amplifier – Example
(a) If a 3 Vpp signal is applied to the input, what voltage do you expect to see at the speaker? (b) What power is delivered?
Solution:
Example:
(a) The CC amplifier has a gain of nearly 1. The output voltage is nearly equal to the input = 3 Vpp.
(b) The power delivered to the speaker is:
= 140 mW
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Follow-up:
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Solution:
Follow-up:
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Solution:
Follow-up:
= 0.183 mW
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Solution:
Follow-up:
The power gain is:
= 0.183 mW
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Solution:
Follow-up:
The power gain is:
= 0.183 mW
= 769
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Electronic Devices
Class-A Power Amplifier – Example
For the 3 Vpp input, what is the input power and what is the power gain? Assume the Darlington b = 10,000.
Solution:
Follow-up:
The power gain is:
= 0.183 mW
= 769
Note that this is approximately 140 mW/0.183 mW
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Electronic Devices
Class-A Power Amplifier – Multisim
The circuit in the previous example can be simulated in Multisim as a check.
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Electronic Devices
Class-A Power Amplifier – Multisim
The circuit in the previous example can be simulated in Multisim as a check.
The input trace (red) and output trace (blue) are nearly on top of each other as expected.
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Electronic Devices
Push-Pull Amplifiers
Push-pull amplifiers use two transistors working together. One conducts on the positive half cycle; the other conducts on the negative half cycle. This is class B operation.
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Electronic Devices
Push-Pull Amplifiers
By adding a forward biased diode, the base-emitter drop of the transistors does not need to be overcome by the signal. This is class AB operation. Notice that both transistors are npn types.
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Electronic Devices
Push-Pull Amplifiers
A complementary symmetry push-pull amplifier uses an npn and a pnp transistor working together on alternate half-cycles.
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Electronic Devices
Push-Pull Amplifiers
A complementary symmetry push-pull amplifier uses an npn and a pnp transistor working together on alternate half-cycles.
The two diodes cause the transistors to be biased into slight conduction. Because of the slight conduction, this is also class AB operation and the transistors conduct slightly more than ½ of the input cycle.
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Electronic Devices
Push-Pull Amplifiers
A complementary symmetry push-pull amplifier uses an npn and a pnp transistor working together on alternate half-cycles.
The two diodes cause the transistors to be biased into slight conduction. Because of the slight conduction, this is also class AB operation and the transistors conduct slightly more than ½ of the input cycle.
Question:
What is the advantage of class AB operation over class B operation?
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Electronic Devices
Push-Pull Amplifiers
A complementary symmetry push-pull amplifier uses an npn and a pnp transistor working together on alternate half-cycles.
The two diodes cause the transistors to be biased into slight conduction. Because of the slight conduction, this is also class AB operation and the transistors conduct slightly more than ½ of the input cycle.
Question:
What is the advantage of class AB operation over class B operation?
Cross-over distortion is eliminated.
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Electronic Devices
Push-Pull Amplifiers
The ac load line for the npn transistor of a complementary push-pull amplifier is shown.
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Electronic Devices
Push-Pull Amplifiers
The ac load line for the npn transistor of a complementary push-pull amplifier is shown.
Notice that the Q point is near the right end of the load line.
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Electronic Devices
Push-Pull Amplifiers
The ac load line for the npn transistor of a complementary push-pull amplifier is shown.
Ic(sat) is determined by the load resistor and is given by:
Notice that the Q point is near the right end of the load line.
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Electronic Devices
Push-Pull Amplifiers – Example
Example:
Draw the ac load line for the npn transistor.
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Electronic Devices
Push-Pull Amplifiers – Example
Example:
Draw the ac load line for the npn transistor.
Solution:
The ac load line is drawn between Ic(sat) and VCC.
+15 V
0.5 A
IC
VCE
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Electronic Devices
Push-Pull Amplifiers
The maximum peak output voltage is always less than the power supply voltage. For the amplifier shown, the maximum peak output will be about ±13 V because at the peak of the input, maximum bias current is required.
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Electronic Devices
Push-Pull Amplifiers
The maximum peak output voltage is always less than the power supply voltage. For the amplifier shown, the maximum peak output will be about ±13 V because at the peak of the input, maximum bias current is required.
For a given load resistor, you can enable a larger output by using smaller bias resistors, higher beta transistors (such as Darlington transistors), or increasing the power supply voltages.
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Electronic Devices
Push-Pull Amplifiers – Multisim
A Multisim simulation of the previous circuit shows clipping on the output when the input exceeds ±13 V. The input is the ±14 V yellow trace; the output is the blue trace and is clipped at ±13 V.
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Electronic Devices
Push-Pull Amplifiers
Question:
Why is the voltage gain of the previous circuit less than 1?
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Electronic Devices
Push-Pull Amplifiers
Each transistor is configured as a CC amplifier.
Question:
Why is the voltage gain of the previous circuit less than 1?
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Electronic Devices
Push-Pull Amplifiers
Darlington transistors have replaced the single transistors in the previous circuit. The bias resistor are larger (less power dissipation) and two more diodes are added. The maximum output can be larger due to the Darlington transistors despite the larger bias resistors.
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Electronic Devices
Push-Pull Amplifiers
Darlington transistors have replaced the single transistors in the previous circuit. The bias resistor are larger (less power dissipation) and two more diodes are added. The maximum output can be larger due to the Darlington transistors despite the larger bias resistors.
Question:
Why are four diodes used in this circuit?
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Electronic Devices
Push-Pull Amplifiers
Darlington transistors have replaced the single transistors in the previous circuit. The bias resistor are larger (less power dissipation) and two more diodes are added. The maximum output can be larger due to the Darlington transistors despite the larger bias resistors.
Question:
Why are four diodes used in this circuit?
There are two base-emitter drops for each polarity of the input.
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Electronic Devices
Push-Pull Amplifiers
The circuit shown is in the lab manual and uses a dc coupled CE amplifier stage to drive the push-pull stage. In this case, the CE amplifier is in the bias path for the push-pull stage.
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Electronic Devices
Push-Pull Amplifiers
The circuit shown is in the lab manual and uses a dc coupled CE amplifier stage to drive the push-pull stage. In this case, the CE amplifier is in the bias path for the push-pull stage.
Question:
How would you adjust R5 for an optimum setting?
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Electronic Devices
Push-Pull Amplifiers
The circuit shown is in the lab manual and uses a dc coupled CE amplifier stage to drive the push-pull stage. In this case, the CE amplifier is in the bias path for the push-pull stage.
Question:
How would you adjust R5 for an optimum setting?
Monitor the dc output voltage and adjust it for 0 V using R5.
0 V
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Electronic Devices
Class-C Amplifiers
Class C amplifiers are biased into conduction much less than 180o. They are usually used in RF applications, such as RF oscillators and modulators.
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Electronic Devices
Class-C Amplifiers
Class C amplifiers are biased into conduction much less than 180o. They are usually used in RF applications, such as RF oscillators and modulators.
The transistor is on when the input signal exceeds |VBB| + VBE. Because class C amplifiers are biased on for a small percentage of time, they can be very efficient.
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Electronic Devices
Class-C Amplifiers
Class C operation is useful in oscillators. The collector circuit has a parallel resonant circuit (“tank”) and oscillations are sustained by the short pulse of collector current on each cycle.
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Electronic Devices
Class-C Amplifiers
The circuit can be set up with clamping bias, where the bias resistor is connected to ground. C1 will charge (through the base-emitter diode) to 0.7 V less than the positive peak.
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Electronic Devices
Class-C Amplifiers
The circuit can be set up with clamping bias, where the bias resistor is connected to ground. C1 will charge (through the base-emitter diode) to 0.7 V less than the positive peak.
Clamping action causes the transistor to be cut off except at the positive peak of the input. The R1C1 time constant needs to be long compared to the period of the signal.
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Electronic Devices
Push-Pull Amplifier -Troubleshooting
If there are no faults in the push-pull amplifier shown, what DC voltage do you expect to read on meter XXM1?
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Electronic Devices
Push-Pull Amplifier -Troubleshooting
If there are no faults in the push-pull amplifier shown, what DC voltage do you expect to read on meter XXM1?
You should see a forward diode drop. If diodes and transistors are matched, the point between the diodes should be at 0 V and the cathode of D2 is one diode drop less.
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Electronic Devices
Push-Pull Amplifier -Troubleshooting
Assume Diode D2 is open. What do you expect to see on the meter now? Explain your answer.
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Electronic Devices
Push-Pull Amplifier -Troubleshooting
Assume Diode D2 is open. What do you expect to see on the meter now? Explain your answer.
You will still see a forward diode drop. This is because there is a path from ground, through the emitter-base junction of Q2, and through R2 to VEE.
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Electronic Devices
Push-Pull Amplifier -Troubleshooting
Assume Diode D2 is open. What do you expect to see on the meter now? Explain your answer.
You will still see a forward diode drop. This is because there is a path from ground, through the emitter-base junction of Q2, and through R2 to VEE.
With a signal source on, the rectified signal will cause a DC voltage to be superimposed.
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Electronic Devices
Key Terms-1
Class A
Power gain
Efficiency
Class B
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Electronic Devices
Key Terms-1
Class A
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